Submitted by Edogowa Conan on Tue, 12/27/2016 - 14:21
Forums:
Hi,
I'm stuck on the last part of the step question where they ask you to show that c^2 is between 1 and 0, but one of the equations they gave us shows that c^2 is negative. I read the hints where they told us to use the first equation given which involves c^2. However, it is that same equation which shows that c^2 is negative.
Help pleas
How exactly does it show that
How exactly does it show that $c^2$ is negative? Do you mean because of the negative sign? If so, what happens if one of $a$ and $b$ is negative? Remember that $-(-1) = +1$.
Instead, you're given that $c$ is a real number, from which you can immediately deduce that $c^2 \geq 0$. It's up to you to show that $c^2 \neq 0$ (hint: contradiction) that immediately tells you that $c^2 > 0$.