Submitted by bogan on Fri, 09/29/2017 - 10:28
Forums:
Hello STEPpers,
RE: Assignment 15, Warm-up Q1.(iiii)(c)
We're told that g(r-1) is non-zero for r running from 1 to n-1
This surely means that g(n-1) and g(n) may be zero.. Not good !
Should this be 1 to n+! instead?
Then you'd be guaranteed that g(n-1) and g(n) are not zero.
The feedback assumes that g(n) is defined so I'm persuaded that the r's should run to n+!
Thanks
BGN
P.S. You can keep the error in the materials- it's good for checking who is awake out there and provides a lesson in checking the small print : )
Agreed, in part!
It should be either $g(r-1) \neq 0$ for $r=1, 2, ..., n $ or $g(r) \neq 0$ for $r=0, 2, ..., n-1 $.
It's actually fine for $g(n) = 0$.