Submitted by jtedds on Mon, 04/03/2017 - 20:51
(i) Let x+iy be a root of the quadratic equation $z^2 +pz+ 1 = 0$ , where p is a real number.
Show that $x^2 − y^2 + px + 1 = 0$ and $(2x + p)y = 0$.
Show further that either $p = −2x$ or $p = −(x^2 + 1)/x$ with $x\neq 0 $.
Hence show that the set of points in the Argand diagram that can (as p varies) represent
roots of the quadratic equation consists of the real axis with one point missing and a
circle. This set of points is called the root locus of the quadratic equation.
(ii) Obtain and sketch in the Argand diagram the root locus of the equation
$pz^2 + z + 1 = 0$ .
(iii) Obtain and sketch in the Argand diagram the root locus of the equation
$pz^2 + p^2z + 2 = 0$ .
I've solved parts (i) and (ii) and attempted to use the same method to solve (iii) where I obtained the equations
$px^2 -py^2 + p^2x +2 = 0$ and $py(2x + p) = 0$
solving the second equation is simple by letting the brackets $2x + p = 0$
However, I've been unable to manipulate the first equation using $y=0$.
Please could you let me know if I'm actually using the right method or there's something I'm missing
Thank you!
Yep, you're certainly on the
Yep, you're certainly on the right lines. If $2x+p = 0$, what can you deduce about $y$ from the other equation? You can find $y$ as a function of $x$.
Secondly, if $y=0$ then your first equation becomes a quadratic in $p$, which you can then solve via the formula.