For the last part,
I let $ T(x) = t(tan x) $ and I showed that $T(x) + T(y) = T(x+y) $
hence using the first part I concluded $ T(x) = Ax = t(tanx) $
to work out $t(u)$ I let $u=tanx$ and hence $x = arctanu + n\pi$
therefore $t(u) = Ax = A (arctan u +n\pi)$
But the solutions say $t(u) = A arctan u$ - to find the most general solution don't you need to add on the $n\pi$ ?
I would be grateful for a quick reply since the STEP exams are this week.
Thanks for all the help so far