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STEP Support Programme

Discussion 2016-2017

Interesting Talk

5 August 2016

If you're having a go at the assignments but fancy a break, why not take a look at this video of a talk given by Dr Vicky Neale?

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Warm up assignment 1

1 August 2016

How do you neatly find the root of the equation for part 4)b)?

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Assignment 1 Warm Down

20 July 2016

Can I give an age for the minister that I can guarantee will be above the second oldest member of the group? I have a list of ages for the other people and a range of values for the minister, so without knowing which list is correct can I just give an age from the smallest range? Or is there any way to narrow down my lists and find an exact age for the minister?

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STEP II 1996 Q11

11 February 2016

Hello,
I've been having a go at this question however can't get the first D.E out. I started off by saying $m(\frac {d^2y}{dt^2}) = m(g-f) - \frac {\lambda (a + y)}{l}$, with $\frac{\lambda a}{l}=mg$, however I'm not certain I've put $f$ in the right place? Even so when I expand the above I get very close to the answer except I'm missing the $g$ term. So i was wondering whether the question meant $y$ is the extension of the elastic band from it's natural length instead of equilibrium length, as this would make my equation work out?

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2006 STEP 3 Q4

15 June 2015

For the last part,

I let $ T(x) = t(tan x) $ and I showed that $T(x) + T(y) = T(x+y) $

hence using the first part I concluded $ T(x) = Ax = t(tanx) $

to work out $t(u)$ I let $u=tanx$ and hence $x = arctanu + n\pi$

therefore $t(u) = Ax = A (arctan u +n\pi)$

But the solutions say $t(u) = A arctan u$ - to find the most general solution don't you need to add on the $n\pi$ ?

I would be grateful for a quick reply since the STEP exams are this week.

Thanks for all the help so far

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What can this forum be used for?

14 June 2015

I am sorry if this is off topics but as an old user of Ask Nrich I have recently discovered this forum and was wondering if, as well as STEP and MAT, this forum could be used to discuss BMO2 problems as well?

Thanks,

tridianprime

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Who else is taking STEP 1 tomorrow?

14 June 2015

(June 15th 2015)
So anxious about having to take STEP 1!

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1997 STEP 3 Q6

13 June 2015

I was able to find the general solution for $y_n $ in terms of $ \theta $:

$y_{n}(\theta)=A\cos n\theta+B\sin n\theta $

using the condition y(0) = 1 I found that A=1

However, I am not able to find the value of B by using the second condition - I have looked at the TSR solutions but I do not understand them.

The official STEP hints and solutions state $ cos (n(\theta + \pi)) = (-1)^{-n} cos (n\theta) $ - how does this help when you are actually substituting in $\theta = cos^{-1} x $ ?

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General questions

13 June 2015

Can you quote formulas from the formula book in STEP? E.g the section titled coordinate geometry in the formula book has useful formulas – in STEP 3 2014 Q3 you could use the perpendicular distance from point to line

Do you get penalised for bad notation? E.g. putting a single implication instead of a double implication

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2001 STEP 3 Q12

3 June 2015

For part (i) I solution I have tried the following. Let $N$ be the number of balls drawn before and including the last white ball drawn. Using the hyper geometric distribution:

\[ P(N \leq n) = \frac{\binom{w}{w} \binom{b}{n-w}}{\binom{b+w}{n}} \]

Which simplifies to:

\[ P(N \leq n) = \frac{b! \times n!}{(b+w)! \times (n-w)!} \]

Also
\[ P(N = n) = P(N \leq n) - P(N \leq n-1) \]
\[ \therefore P(N = n) = \frac{b! \times n!}{(b+w)! \times (n-w)!} - \frac{b! \times (n-1)!}{(b+w)! \times (n-1-w)!} \]

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Useful Links

Underground Mathematics: Selected worked STEP questions

STEP Question database

University of Cambridge Mathematics Faculty: What do we look for?

University of Cambridge Mathematics Faculty: Information about STEP

University of Cambridge Admissions Office: Undergraduate course information for Mathematics

Stephen Siklos' "Advanced Problems in Mathematics" book (external link)

MEI: Worked solutions to STEP questions (external link)

OCR: Exam board information about STEP (external link)

AMSP (Advanced Maths Support programme): Support for University Admission Tests (external link)