Submitted by Jeff Golland on Tue, 05/08/2018 - 14:16
Part (ii) of this question implies that the denominator of E(x) is (alpha + beta). I think it should just be beta. You have to create Probability Density Functions for X and Y: they are not Poisson because not all integer outcomes are possible. They are Poisson divided by e to the minus lambda times beta (for X); and divided by e to the minus lambda times alpha (for Y). This also has consequences for the variance calculations.
Which Assignment?
Can you tell me which assignment S2 2013 Q12 is on? I've had a look though and cannot find it!
q12 S2 2013
Found it here https://mathsorchard.weebly.com/uploads/2/7/3/1/27311819/step_2_2013.pdf
Found it here https:/
Found it here https://mathsorchard.weebly.com/uploads/2/7/3/1/27311819/step_2_2013.pdf
It's OK I've worked out why
It's OK I've worked out why the Step solution is correct. No further comments needed.