Hi - the materials from this day are now available here .

Good luck with your preparation!

For the integration section. I got the limits the wrong way round but then did the integration correctly so would I get the method marks for the integration despite my limits being the wrong way round and getting the negative answer

Hi,

I obtained 3 equations :
sin (2nx) = 0
cos(2nx) = 1
cos(2nx) = -1/2
When attempting the question I stated that m=n, and did not get a solution within the range. The integral solution treated these to be different which I don’t understand since they are both positive integers. Why is it also necessary to state each of the solutions have their own integer coefficients of pi (m, p and q). This meant I got no solutions in the range when I attempted the question once I had also used n = 2k and n = 2k +1.

Please can someone explain why it isn’t a^3/9 for all a greater than or equal to two. In the mark scheme it says it’s always bigger than 3a-6 but then let’s M(a) be 3a-6 ? Mark scheme at: https://correspondence.maths.org/sites/correspondence.maths.org/files/fe...

I have obtained a(x) and b(x) but had to do two substitutions v = u/x and t = v'(x) to get the answer. However the mark scheme (integral) states a more efficient argument that since the equation is linear in u and it's derivatives the general solution is
u = Ax + Be^(-x) which I don't understand!

any help would be much appreciated

Hi,

I am trying to prove that:

cosh x + cosh 2x + cosh 3x + … + cosh nx = cosh ((n+1)x/2) sinh(nx/2) cosech(x/2)

So far I have tried to use a similar identity for hyperbolics from de moivre's theorem and try to evaluate even terms but this would only allow me to evaluate a single term in the sequence..

any help would be much appreciated!

My Further Mathematics modules are M1 and D1, and therefore my base statistics knowledge isn't typically up to the standard that's required to answer a STEP question.

Is it recommended to learn it regardless to have the opportunity to answer more questions and possibly get a better mark in one, or to focus on the topics that I'm already strong in given that only the six best answers are marked?

Thanks in advance.

2012 STEP 1 Q11

For 2(ii), I cannot wrap my head around why a(P)=0.5(a(A)+a(B))

Where a stands for acceleration and the above expression states acceleration of object P is equal to half the sum of acceleration of objects A and B. The solution for this qn states "If A goes up the slope by 5cm and B goes up by 3cm then P will go down by 0.5(5+3) = 4cm".

Why is this so? How is the displacement then directly proportionally related to acceleration. Is it by the SUVAT eqn s=ut+0.5at^2

Really appreciate your help in this

I've been talking to some guys currently studying at Cambridge, they recommend starting in January (if you get an offer) and doing 1 of STEP II and 1 of STEP III per week, can anyone confirm that this works? Also, what kind of scores should I expect to get to begin with? I've been getting ~70 or 80 on pre-2002 STEP IIs and >100 on pre-2002 STEP Is